-y^2+13y-1=0

Solution for -y^2+13y-1=0 equation:

-y^2+13y-1=0

We add all the numbers together, and all the variables

-1y^2+13y-1=0

a = -1; b = 13; c = -1;
Δ = b2-4ac
Δ = 132-4·(-1)·(-1)
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{165}}{2*-1}=\frac{-13-\sqrt{165}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{165}}{2*-1}=\frac{-13+\sqrt{165}}{-2}
$